| #include <algorithm> |
| #include <cstring> |
| #include <iostream> |
| #include <set> |
| #include <tuple> |
| #include <utility> |
| #include <vector> |
| using namespace std; |
|
|
| const int INF = 1000000000; |
| const int LIM = 1000002; |
| const int LIM2 = 2000002; |
| const int LIM3 = 23; |
|
|
| int R, C, N, K; |
| int H[LIM], S[LIM]; |
| vector<tuple<int, int, int>> A; |
| pair<int, int> curr; |
| int M; |
| int children[LIM2][2]; |
| int parent[LIM2][LIM3]; |
| int high[LIM2]; |
|
|
| struct UnionFind { |
| int N; |
| vector<int> root, rank, node; |
|
|
| UnionFind(int _N) : N(_N), root(_N), rank(_N, 0), node(_N) { |
| for (int i = 0; i < N; i++) { |
| root[i] = i; |
| node[i] = M; |
| children[M][0] = children[M][1] = -1; |
| high[M++] = INF + 1; |
| } |
| } |
|
|
| int find(int i) { |
| if (root[i] != i) { |
| root[i] = find(root[i]); |
| } |
| return root[i]; |
| } |
|
|
| void merge(int i, int j, int e) { |
| i = find(i); |
| j = find(j); |
| if (i == j) { |
| return; |
| } |
| if (rank[i] > rank[j]) { |
| swap(i, j); |
| } |
| root[i] = j; |
| if (rank[i] == rank[j]) { |
| rank[j]++; |
| } |
| |
| children[M][0] = node[i]; |
| children[M][1] = node[j]; |
| high[M] = e; |
| node[j] = M++; |
| } |
| }; |
|
|
| struct HeavyLightTree { |
| int heavy[LIM2]; |
| int root[LIM2], treePos[LIM2], inv[LIM2]; |
| int ind, L[LIM2], R[LIM2]; |
| multiset<int> S, S2; |
|
|
| int dfs(int v) { |
| L[v] = ind++; |
| for (int i = 0; i < LIM3 - 1; i++) { |
| int p = parent[v][i]; |
| if (p < 0) { |
| break; |
| } |
| parent[v][i + 1] = parent[p][i]; |
| } |
| int size = 1, maxSubtree = 0; |
| for (int u : children[v]) { |
| if (u < 0) { |
| continue; |
| } |
| parent[u][0] = v; |
| int subtree = dfs(u); |
| if (subtree > maxSubtree) { |
| heavy[v] = u; |
| maxSubtree = subtree; |
| } |
| size += subtree; |
| } |
| R[v] = ind - 1; |
| return size; |
| } |
|
|
| void init() { |
| fill_n(heavy, M, -1); |
| ind = 0; |
| dfs(M - 1); |
| for (int i = 0, currentPos = 0; i < M; i++) { |
| if (parent[i][0] == -1 || heavy[parent[i][0]] != i) { |
| for (int j = i; j != -1; j = heavy[j]) { |
| root[j] = i; |
| inv[currentPos] = j; |
| treePos[j] = currentPos++; |
| } |
| } |
| } |
| S.clear(); |
| S2.clear(); |
| S.insert(-1); |
| } |
|
|
| void update(int i, bool ins) { |
| if (ins) { |
| S.insert(treePos[i]); |
| S2.insert(L[i]); |
| } else { |
| S.erase(S.find(treePos[i])); |
| S2.erase(S2.find(L[i])); |
| } |
| } |
|
|
| int find_closest_ancestor_set(int i) { |
| while (i >= 0) { |
| int j = root[i]; |
| int k = *prev(S.lower_bound(treePos[i] + 1)); |
| if (k >= treePos[j]) { |
| return inv[k]; |
| } |
| i = parent[j][0]; |
| } |
| return -1; |
| } |
|
|
| bool subtree_has_set_M(int i, bool inc) { |
| auto it = S2.lower_bound(L[i] + (inc ? 0 : 1)); |
| return it != S2.end() && *it <= R[i]; |
| } |
| }; |
|
|
| HeavyLightTree HLT; |
|
|
| void update_cell(int i, bool ins) { |
| |
| int s = S[i]; |
| if (s >= H[i]) { |
| return; |
| } |
| |
| int d = ins ? 1 : -1; |
| curr.first += d; |
| |
| for (int j = LIM3 - 1; j >= 0; j--) { |
| if (parent[i][j] >= 0 && high[parent[i][j]] > s) { |
| i = parent[i][j]; |
| } |
| } |
| |
| if (!ins) { |
| HLT.update(i, ins); |
| } |
| |
| if (!HLT.subtree_has_set_M(i, true)) { |
| |
| int a = HLT.find_closest_ancestor_set(i); |
| |
| |
| if (a < 0 || HLT.subtree_has_set_M(a, false)) { |
| curr.second += d; |
| } |
| } |
| |
| if (ins) { |
| HLT.update(i, ins); |
| } |
| } |
|
|
| pair<long long, long long> solve() { |
| A.clear(); |
| |
| cin >> R >> C; |
| N = R * C; |
| for (int i = 0, j; i < N; i++) { |
| cin >> H[i]; |
| if ((j = i - C) >= 0) { |
| A.emplace_back(-min(H[i], H[j]), i, j); |
| } |
| if (i % C > 0 && (j = i - 1) >= 0) { |
| A.emplace_back(-min(H[i], H[j]), i, j); |
| } |
| } |
| for (int i = 0; i < N; i++) { |
| cin >> S[i]; |
| } |
| |
| |
| M = 0; |
| UnionFind U(N); |
| sort(A.begin(), A.end()); |
| for (auto t : A) { |
| U.merge(get<1>(t), get<2>(t), -get<0>(t)); |
| } |
| memset(parent, -1, sizeof(parent[0]) * M); |
| HLT.init(); |
| |
| curr = make_pair(0, 0); |
| for (int i = 0; i < N; i++) { |
| update_cell(i, 1); |
| } |
| |
| cin >> K; |
| pair<long long, long long> ans{0, 0}; |
| int prevY = 0; |
| while (K--) { |
| int i, j; |
| cin >> i >> j; |
| i = (i ^ prevY) - 1; |
| j = (j ^ prevY) - 1; |
| i = i * C + j; |
| update_cell(i, 0); |
| cin >> S[i]; |
| S[i] ^= prevY; |
| update_cell(i, 1); |
| ans.first += curr.first; |
| ans.second += curr.second; |
| prevY = curr.second; |
| } |
| return ans; |
| } |
|
|
| int main() { |
| int T; |
| cin >> T; |
| for (int t = 1; t <= T; t++) { |
| auto ans = solve(); |
| cout << "Case #" << t << ": " << ans.first << " " << ans.second << endl; |
| } |
| return 0; |
| } |
|
|